(4x)^2-16x=30

Solution for (4x)^2-16x=30 equation:

(4x)^2-16x=30

We move all terms to the left:

(4x)^2-16x-(30)=0

a = 4; b = -16; c = -30;
Δ = b2-4ac
Δ = -162-4·4·(-30)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{46}}{2*4}=\frac{16-4\sqrt{46}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{46}}{2*4}=\frac{16+4\sqrt{46}}{8}
$